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-5x^2-160x-1277=0
a = -5; b = -160; c = -1277;
Δ = b2-4ac
Δ = -1602-4·(-5)·(-1277)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-2\sqrt{15}}{2*-5}=\frac{160-2\sqrt{15}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+2\sqrt{15}}{2*-5}=\frac{160+2\sqrt{15}}{-10} $
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